(325+326+327+328) is divisible by : (1) 11 (2) 16 (3) 25 (4) 30 Leave a Comment / Blog / By URVASHI GARG Solution: 325+326+327+328 = 325(1+3+32+33) =325(1+3+9+27) =325*40, Which is clearly divisible by 30.