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The length of a rectangle is less than twice its breadth by 1 cm. The length of its diagonal is 17 cm. Find its length and breadth A. 15 cm, 8 cm B. 13 cm, 4 cm C. 10 cm, 6 cm D. 8 cm, 9 cm

Solution

L = 2B – 1, Diagonal = 17. D² = L²+ B²
⇒ 289 = (2B –1)²+ B²⇒ B = 8 & L = 15.
Also 8, 15, 17 is a Pythagorean triplet.
So answer can be reached directly.

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