The sum of two numbers is 45. One of the numbers exceeds the other by 9. Find the numbers. (a) 19,28 (b)15,30 (c)18,27 (d)17,28

Solution

Let the number be x.
Then the other number = x + 9
Sum of two numbers = 45
According to the question, x + (x + 9) = 45
⇒ 2x + 9 = 45
⇒ 2x = 45 – 9 (transposing 9 to the R.H.S changes to -9)
⇒ 2x = 36
⇒ 2x/2 = 36/2 (divide by 2 on both the sides)
⇒ x = 18
Therefore, x + 9 = 18 + 9 = 27
Therefore, the two numbers are 18 and 27.