Gunjo Pachauri

Solution Let the total number of matches played be x.The team won around 10 matches, and the team’s winning percentage was 40%.40/100 × x = 1040x = 10 × 10040x = 1000x = 1000/40= 100/4= 2Hence, the team played 25 matches.

Solution Since every polyhedron satisfies Euler’s formula, therefore checking if polyhedron can have 10 faces, 20 edges and 15 vertices.No. of Faces (F) = 10No. of Vertices (V) = 15No. of Edges (E) = 20By Using Euler’s formula: F + V – E = 2 and Substituting the values, we get⇒ 10 + 15 –

Solution A leap year can have 52 Sundays or 53 Sundays. In a leap year, there are 366 days out of which there are 52 complete weeks & remaining 2 days. Now, these two days can be (Sat, Sun) (Sun, Mon) (Mon, Tue) (Tue, Wed) (Wed, Thur) (Thur, Friday) (Friday, Sat).So there are total 7

Solution The 2nd and the 7th terms are (a + d) and (a + 6d) respectively. The ratio of these terms is 1/3. Solving this ratio, we get 2a = 3d. The 5th term is (a + 4d) = 11. Substituting for a, we get a = 3 and d = 2. Therefore, the 15th

Solution Let x + 543 + 5.43 = 603.26.Then, x = 603.26 – (543 + 5.43)= 603.26 – 548.43 =54.83Missing digit = 8.

Solution We know thatV + F – E = 2⇒ 10 + 18 – E = 2⇒ 28 – E = 2⇒ E = 28 – 2 = 26Hence, the required value of E = 26

Solution Given: expressions 3a−b+9 , −b−9 , 3a−b−9We need to subtract 3a−b−9 from the sum of 3a−b+9 and −b−9The sum of the first two terms, −b−9 and 3a−b+9 will be3a−b+9+(−b−9)=3a−b+9−b−9=3a−2bNow subtracting 3a−b+9 from 3a−2b , we get3a−2b−(3a−b−9)=3a−2b−3a+b=9=−b+9

Solution Scale of map = Size drawnActual size= 10cm1000cm (because 10 m = 1000 cm)= 1100Thus, the scale is 1:100.

Solution L = 2B – 1, Diagonal = 17. D² = L²+ B²⇒ 289 = (2B –1)² + B²⇒ B = 8 & L = 15.Also 8, 15, 17 is a Pythagorean triplet.So answer can be reached directly.

Solution Given: 5x²−2 , x=3We need to find the value of 5x²−2 at x=3We will put 3 in place of x in the expression 5x²−2Therefore, the value of the expression will be5x²−2=5(3)²−2=5(3)−2=45−2=43