URVASHI GARG

Solution: 5808 =2*2*2*2*3*11*11 = 22*22*112*3 Therefore, when 5808 is multiplied by 3,  then it will be perfect square number. Then the option is (4) 3

(1) 539.712 cm2 (2) 538.721 em2 (3) 540.712 em2 (4) 539.217 cm2 Solution: Area of paper=Area of square +Area of equilateral triangle =1/2 (diagonal)2+ √3/4*(side)2 =1/2*32*32+√3/4*8*8 = 512 + 16 * 1.732 = 512 + 27.712 = 539.712 cm2 (Note: Diagonal of a square =√2 side) Then the option is (1) 539.712 cm2

(1) 25 (2) 30 (3) 35 (4) 20 Solution: Let the number of students be n. So, each of n students got 2n chocolates Total no. of chocolates = (2n)*n = 800 ⇒ 2n2 =800 ⇒ n2=400 ⇒ n=20 Then the option is (4)

(1) 20 (2)30 (3)40 (4)50 Solution: Let the original number of boys and girls be x and y respectively. Then x/y-15=2/1 ⇒ x = 2y – 30    ……….(i) Again, x-45/y-15=1/5 ⇒ 5x-225=y-15 ⇒ 5x= y-15+225 ⇒ 5(2y-30) = y+210 [From equation (i)) ⇒ 10y-150=y+210 ⇒ 10y-y=210+150 ⇒ 9y = 360 ⇒ y=360/9 = 40

Solution: Two angles of triangle= 4x and 5x (let)According to the question.2(4x+ 5x) = 180∘⇒ 18x= 180∘⇒ x = 180∘/18 = 10∘:. The smallest angle= 4x = 4*10 = 40∘Then the answer is 40∘.

Solution: First number * second number  = LCM * HCF Let the second number be x. :. lOx = 30 * 5 ⇒x= 30*5/10 = 15 Then the option is (3) 15

Solution: According to the question, Total marks = 71* 14= 994 Correct total marks = 994+(56-42) + (32-74) = 994+14-42 = 966 Required average = 966/14 = 69 Then the option is (3) 69

Solution: Distance = Speed * Time = (40*6 1/4) km = (40*25/4) km = 250km New speed= 50 kmph :. Required time = Distance/Speed = 250/50 = 5 hours Then the answer is 5 hours.

(1) yz (2) xz/y (3) xy/z (4) xyz Solution: Product of two numbers= HCF * LCM⇒ Number = zx and zy:. zx*zy = z*LCM⇒ LCM =xyz Then the option is (4) xyz

Solution: 9√x = √12+√147 ⇒9√x = 2√3+7√3 =√3 (2+7) ⇒9√x = 9√3 ⇒x=3 Then the answer is 3.