URVASHI GARG

(1) 6.5 km. (2) 5.5 km. (3) 6 km. (4)5 km. Solution: Let time taken to reach school at 4 kmph be x hrs.Then time taken to reach school at 5 kmph = (x+15/60)hrs Since, distance is equal. ,’. 4x=5(x+15/60) x= 5/4 hrs. Hence, distance between school & house = 4*5/4km= 5km Then the answer […]

(1) 63 (2) 61 (3) 65 (4) 64 Solution: √1+x/961= 32/31 Squaring  both sides, 1+ x/961= (32/31)2= 1024/961 ⇒ x/961= 1024/961-1=1024-961/961= 63/961 ⇒ x= 63 Then the option is (1) 63

(1) 0 (2) 1 (3) 2 (4) 3 Solution: x2-3x+1=0 ⇒ x2+1= 3x ⇒ x2+1/x= 3x/x ⇒ x+1/x = 3 Then the answer is 3.

(1) 640 (2) 1280 (3) 256 (4) 160 Solution: According to question, nth term of a GP = arn-1 :. 8th term = 5*(2)8-1 5*(2)7 = 5*128 = 640 Then the option is (1) 640

Solution: Let third number be x. :. Second number = 3x and first number = 3x/2 Now , x+3x+3x/2= 3*44 ⇒ 8x+3x/2 = 3*44 ⇒ 11x= 6*44 ⇒ x= 6*44/11= 24 :. The largest number = 3x = 3*24= 72 Then the option in (2) 72

(1) 39 minutes (2) 46 minutes (3) 40 minutes (4) 45 minutes Solution: Part of the tank filled by pipes A and B in 1 minute = 1/36+1/45= 5+4/180 = 9/180 = 1/20 Part of the tank filled by these pipes in 7 minutes =7/20 Remaining unfilled part = 1-7/20= 20-7/20= 13/20 When all three

(1) 100 (2) 92 (3) 91 (4) 50 Solution: Number of digits from 1 to 9 = 9Number of digits used in writingfrom 10 to 50= 41 x 2 =82:. Total digits =82 + 9 = 91 Then Option is (3) 91

(1) 15 (2) 60 (3) 36 (4) 45 Solution: If the numbers be 3x and 4x, then their LCM = 12x =12x= 180⇒x=225/15=15 =First number = 3x = 45 ⇒Then the option is (4) 45

(1) 136 square cm. (2) 120 square cm. (3) 125 square cm. (4) 100 square cm. Solution: Let the length, breadth and height of the parallelopiped be a, b and c cm respectively. :. a+ b+ c= 20 2 (ab + bc + ca) = 264 :. (a+b+c)2= a2+b2+c2+2(ab + bc+ ca) ⇒400= a2+b2+c2+264 ⇒a2+b2+c2=

Solution: Let the last number be x.According to the question,18 x 10 + 11 x 20 + x= 30 x 15⇒ 180 + 220 + x = 450⇒400 +x= 450 ⇒x=450-400=50 Then the answer is 50