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URVASHI GARG

A moving train passes a platform 50 metres long in 14 seconds and a lamp-post in 10 seconds. The speed of the train is

(1) 24 km/hr. (2) 36 km/hr. (3) 40 km/hr. (4)45 km/hr. Solution: ⇒Suppose length of train be x  According to question x+50/14= x/10 ⇒ 14x = 10x+500 ⇒ 4x= 500 ⇒ x= 500/4=125m Therefore, speed = 125/10*18/5= 45kmph

A moving train passes a platform 50 metres long in 14 seconds and a lamp-post in 10 seconds. The speed of the train is Read More »

By walking 5/3 of usual of speed a student reaches school 20 minutes earlier. Find his usual time.

(1) 45 Minutes (2) 50 Minutes (3) 60 Minutes (4) None of these Solution: 5/3 of usual 3/5 of usual time as he reaches earlier. = 3/5 usual time + 20 Minutes= Usual time 20 minutes = (1-3/5) usual time = 2/5 usual time Usual time = 20*5/2= 50 Minutes Then answer is 50 minutes.

By walking 5/3 of usual of speed a student reaches school 20 minutes earlier. Find his usual time. Read More »