Question: Factories a² + 3a – 88
(a-8) (a+11)
(a-9) (a+12)
(a-2) (a-6)
(a-4) (a-5)
Solution
To factories a² + 3a – 88, we will find two numbers p and q such that p + q = 3 and pq = – 88.
Now, 11 + (-8) = 3
And 11 x (-8) = – 88
Splitting the middle term 3a in the given quadratic as 11a – 8a, we get:
a² + 3a – 88 = a² + 11a – 8a – 88
= (a² + 11a) – (8a + 88)
= a(a + 11 ) – 8(a + 11)
= (a – 8)(a + 11)
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