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Find the value of a² + b² + 3ab , at a = 1 and b = –2:(a)=1(b)= -1(c)= 5(d)=4

Solution

Value of a² + b² + 3ab , at a = 1 and b = – 2
= (1)2 + (–2)2 + 3 (1)(–2)
= 1 + 4 – 6
= 5 – 6
= – 1