Find the value of “p” from the polynomial x2 + 3x + p, if one of the zeroes of the polynomial is 2.(A)20 (B) 30 (C) -10 (D) 10

Solution

As 2 is the zero of the polynomial.
We know that if α is a zero of the polynomial p(x), then p(α) = 0
Substituting x = 2 in x2 + 3x + p,
⇒ 22 + 3(2) + p = 0
⇒ 4 + 6 + p = 0
⇒ 10 + p = 0
⇒ p = -10