(1) yz (2) xz/y (3) xy/z (4) xyz
Solution:
Product of two numbers
= HCF * LCM
⇒ Number = zx and zy
:. zx*zy = z*LCM
⇒ LCM =xyz
Then the option is (4) xyz
(1) yz (2) xz/y (3) xy/z (4) xyz
Product of two numbers
= HCF * LCM
⇒ Number = zx and zy
:. zx*zy = z*LCM
⇒ LCM =xyz
Then the option is (4) xyz