Solution
We have to solve these two equations
5x + 4y = 20
x + 2y = 4
Letβs we pick the second equation,
x = 4 β 2y
Now substituting the value of x in the other equation.
5(4 β 2y) + 4y = 20
20 β 10y + 4y = 20
-6y = 0
y = 0
Finding out the value of x by substituting the value of y in the equation,
x = 4 β 2y
x = 4
(4, 0) is the solution to this pair of linear equations.
