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The LCM of two numbers is 30 and their HCF is 5. One of the numbers is 10. The other is :    (1) 20 (2)25 (3) 15 (4) 5

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Solution:

First number * second number 

= LCM * HCF

Let the second number be x.

:. lOx = 30 * 5

⇒x= 30*5/10 = 15

Then the option is (3) 15

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