(1) 20 (2)30 (3)40 (4)50
Solution:
Let the original number of boys and girls be x and y respectively.
Then
x/y-15=2/1
⇒ x = 2y – 30 ……….(i)
Again, x-45/y-15=1/5
⇒ 5x-225=y-15
⇒ 5x= y-15+225
⇒ 5(2y-30) = y+210 [From equation (i))
⇒ 10y-150=y+210
⇒ 10y-y=210+150
⇒ 9y = 360
⇒ y=360/9 = 40
Then the option is (3)