The sum of the squares of two consecutive natural numbers is 145. Find those numbers. A. 6,7B. 10,11C. 8,9D. 10,9 Leave a Comment / Blog / By Gunjo Pachauri March 18, 2024 Solution x²+ (x + 1)² = 145⇒2x ²+ 2x + 1 = 145⇒2x ² + 2x – 144 = 0⇒x ² + x – 72 = 0⇒x(x + 9) – 8(x + 9) = 0⇒x = -9,8