Question: What is the smallest number that leaves a remainder of 1 when divided by 2, 3, 4, and 5?
A) 61
B) 121
C) 241
D) 61
Solution:
The smallest number that leaves a remainder of 1 when divided by any set of numbers is 1 more than the least common multiple (LCM) of those numbers.
LCM of 2, 3, 4, 5 = 60.
Thus,60+1=61.
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