Using the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case (i) p(x) = 2x³+x²–2x–1, g(x) = x+1
Solution p(x) = 2x³+x²–2x–1, g(x) = x+1g(x) = 0⇒ x+1 = 0⇒ x = −1∴Zero of g(x) is -1.Now,p(−1) = 2(−1)³+(−1)²–2(−1)–1= −2+1+2−1= 0∴By the given factor theorem, g(x) is a factor of p(x).
