Blog

(1) 45 Minutes (2) 50 Minutes (3) 60 Minutes (4) None of these Solution: 5/3 of usual 3/5 of usual time as he reaches earlier. = 3/5 usual time + 20 Minutes= Usual time 20 minutes = (1-3/5) usual time = 2/5 usual time Usual time = 20*5/2= 50 Minutes Then answer is 50 minutes.

Solution We have to solve these two equations5x + 4y = 20x + 2y = 4Let’s we pick the second equation,x = 4 – 2yNow substituting the value of x in the other equation.5(4 – 2y) + 4y = 2020 – 10y + 4y = 20-6y = 0y = 0Finding out the value of x

Solution The 2nd and the 7th terms are (a + d) and (a + 6d) respectively. The ratio of these terms is 1/3. Solving this ratio, we get 2a = 3d. The 5th term is (a + 4d) = 11. Substituting for a, we get a = 3 and d = 2. Therefore, the 15th

Solution The 2nd and the 6th terms are (a + d) and (a + 5d) respectively. The ratio of these terms is 2/5. Solving this ratio, we get 3a = 5d. The 8th term is (a + 7d) = 26. Substituting for a, we get a = 5 and d = 3. Therefore, the 10th

Solution Value of a² + b² + 3ab , at a = 1 and b = – 2= (1)2 + (–2)2 + 3 (1)(–2)= 1 + 4 – 6= 5 – 6= – 1

(1) 3/7 (2) 2/3 (3) 4/5 (4) 1/2 Solution: 2/5 and 4/9 = 0.40 and 0.44 Fraction between these two = 3/7= 0.42 Then the answer is option (1)

Solution Given,a = 5 + 2√6b = 1/a= 1/(5 + 2√6)Rationalizing the denominator, we get;b = [1/(5 + 2√6)] [(5 – 2√6)/(5 – 2√6)]= (5 – 2√6)/ [(5)2 – (2√6)2]= (5 – 2√6)/ (25 – 24)= 5 – 2√6Now,a² + b²= (a + b)² – 2ab= (5 + 2√6 + 5 – 2√6)2 – 2(5

Solution Let the number be 3x,3x+3 and 3x+6 3x+3x+3+3x+6=72 ⇒9x+9=72 ⇒9x=72-9=63 ⇒x=63/9=7  Largest number: =3x+6=3*7+6=27 Than the answer is 27.

Solution Let the breadth of floor be x metre. :. Length = (x + 20) metre :. Area of the floor =(x+ 20) x sq. metre According to question. (x + 10) (x + 5) = x (x + 20) ⇒x² + 15x + 50 = x² + 20x ⇒ 20x = 15x + 50

Solution: 325+326+327+328 = 325(1+3+32+33) =325(1+3+9+27) =325*40, Which is clearly divisible by 30.