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A bag contains 4 blue, 6 green, and 5 red

Question: A bag contains 4 blue, 6 green, and 5 red marbles. If one marble is drawn at random, what is the probability that it is not blue?
(A) 5⁄15
(B) 11⁄15
(C) 1⁄3
(D) 4⁄15


Solution:

Total marbles = 4 (blue) + 6 (green) + 5 (red) = 15.
Number of non-blue marbles = 6 (green) + 5 (red) = 11.
Thus, the probability of drawing a marble that is not blue:
P (not blue) = 11⁄15

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