4. Odd and Even Numbers

Introduction to Odd and Even Numbers

Definition:

  • Even numbers: Whole numbers that are divisible by 2 without a remainder. Examples: 0,2,4,6,8,…
  • Odd numbers: Whole numbers that are not divisible by 2. Examples: 1,3,5,7,9,…

Key Properties of Even and Odd Numbers:

  1. The last digit of an even number is 0,2,4,6,or 8
  2. The last digit of an odd number is 1,3,5,7,or 9
  3. Sum/Difference of Two Numbers:
    • Even +/− Even = Even.
    • Odd +/− Odd = Even.
    • Even +/− Odd = Odd.
  4. Product of Two Numbers:
    • Even × Even = Even.
    • Odd × Odd = Odd.
    • Even × Odd = Even.

Basic Examples

  1. Example 1: Is 245 odd or even?
    Solution: Look at the last digit (5), which is odd. Hence, 245 is an odd number.
  2. Example 2: Add 14 (even) and 27 (odd).
    Solution: 14 + 27 = 41 (odd)
  3. Example 3: Multiply 8 (even) and 9 (odd).
    Solution: 8 × 9 = 72 (even)

Intermediate Concepts

1. Checking Large Numbers:
For any number, focus only on the last digit to determine if it is odd or even.

  • Example: 2457682 → Last digit is 2. Therefore, 2457682 is even.

2. Sequences of Odd and Even Numbers:
Odd and even numbers alternate in a sequence.

  • Example: 1,2,3,4,5,6,…

3. Division by 2:

  • If the quotient of a number divided by 2 is an integer, the number is even.
  • If not, the number is odd.
    • Example: 45 ÷ 2 = 22.5 → 45 is odd.
    • Example: 88 ÷ 2 = 44 → 88 is even.

Advanced Concepts

1. Difference of Consecutive Even/Odd Numbers:
The difference between two consecutive even or odd numbers is always 22.

  • Example: 1210=2,1917=2.12 – 10 = 2, \quad 19 – 17 = 2.

2. Product of Consecutive Numbers:
The product of two consecutive integers is always even (one number is always even).

  • Example: 6×7=42(even).

 

3. Sum of  first n consecutive Even Numbers:
      = n ( n + 1 )

  • Example: Sum of the first 5  even numbers:

             2 + 4 + .. + 2 x 5

             2 + 4 + .. + 10= 5 ( 5 + 1) = 30

  • Example: Sum of the first 50  even numbers:

             2 + 4 + 6 + 8 + 10 … + 2 x 50  = 50( 50 + 1) =  2550

4. Sum of first n consecutive Odd Numbers:
The sum of the first nn odd numbers is a perfect square:

1+3+5++(2n1)=n2.1 + 3 + 5 + \dots + (2n – 1) = n^2.

  • Example: Sum of the first 55 odd numbers: 1+3+5+7+9=52=25.1 + 3 + 5 + 7 + 9 = 5^2 = 25.

5. Sum of n Numbers in a series Or Sum of Consecutive n Numbers: :

In a number series difference between any 2 consecutive numbers is same.

Examples of number series 

  • 1, 2, 3, 4, 5, 6
  • 2, 4, 6, 8, 10 ( series of first n Even numbers )
  • 1, 3, 5, 7, 9 ( series of first n Odd numbers )
  • 10, 20, 30, 40, 60
  • 10, 14, 18, 22, 26

The sum of the n n consecutive numbers or series of n numbers = \(\Large  \mathtt{\frac{( first\ number\ +\ last\ number) \times \ n}{2}} \) 

  • Example: Sum of the first 5  natural numbers:

          1+2+3+4+5 = \(\Large  \mathtt{\frac{( 1 + 5) \times \ 5}{2}} \)

                                = \(\Large  \mathtt{\frac{ 6 \times \ 5}{2}} \)

                                = 15

  • Example: Sum of the consecutive numbers from 10 to 20:

      10+11+12+….+20 = \(\Large  \mathtt{\frac{( 10 + 20) \times \ 11 }{2}} \)

                                = \(\Large  \mathtt{\frac{ 30 \times \ 11}{2}} \)

                                = 165

6 . Finding Nth term in the number series or count of numbers in series: :

 Assume :

     first term in series = f

     count of terms in series i.e. count of numbers in series = n

    difference between 2 terms in series = d   

Nth term in a series = l

Then –

               l = f + (n-1) x d

Last term =

First term + ( Count of terms in the series – 1 ) x Difference between 2 consecutive terms of series

 

Very Advanced Concepts

1. Modular Arithmetic with Odd and Even Numbers:

  • Even numbers can be written as 2k (where k is an integer).
  • Odd numbers can be written as 2k+ 1 (where k is an integer).
  • Operations:
    • Even + Even 0(mod 2)\equiv 0 (\text{mod } 2)
    • Odd + Odd 0(mod 2)\equiv 0 (\text{mod } 2)
    • Even + Odd 1(mod 2)\equiv 1 (\text{mod } 2)

 

Practice Questions with Solutions

 

1. Determine if 739739 is odd or even.
Solution: Last digit is 99, so 739739 is odd.

2. What is the sum of all odd numbers between 11 and 1515?
Solution:

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 = 64.

=

= \( \large 8^2 \)

=  64

3.  The product of any three consecutive integers is always even or odd  ?
Solution: In a series of 3 consecutive numbers, one number is always even, so the product is even.

4.  Identify if 246801246801 is odd or even.
Solution: Last digit is 11, so 246801246801 is odd.

5. What is the sum of 9999 odd numbers starting from 11?
Solution:

Sum=992=9801.\text{Sum} = 99^2 = 9801.

6. Determine the smallest even number divisible by  3 and 5.

Solution: LCM of 3and 5=15

but 15 is not even number, so we need to find the smallest multiple of 15 which is even.

Thus smallest even number divisible 3 and 5 = 15 x 2 = 303, 4, \text{and } 6 = 12

7. Is the sum of 23,34,and 4123, 34, \text{and } 41 odd or even?
Solution:

23+34+41=98(even).23 + 34 + 41 = 98 \quad \text{(even)}.

8. Find the largest odd factor of 120120.
Solution:
Prime factorisation: 120=23×3×5120 = 2^3 \times 3 \times 5.

Largest odd factor: 3×5=153 \times 5 = 15

9. Can the product of 1010 with odd numbers be even?
Solution: Yes, the product of even number with odd numbers is always even.

10. If xx is even, prove that x2x^2 is even.
Solution: Square of any even number is even because 2k×2k=4k22k \times 2k = 4k^2

11. Is the sum of two even numbers always even?
Solution: Yes, 2m+2n=2(m+n)2m + 2n = 2(m+n) which is even.

12. Calculate the sum of first 5050 even numbers.
Solution:

Sum=2(1+2++50)=2×50×512=2550.\text{Sum} = 2(1 + 2 + \dots + 50) = 2 \times \frac{50 \times 51}{2} = 2550.

13. Determine the smallest odd number greater than 10001000.
Solution: 10011001.

14. Prove that 2n+12^{n+1} is always even.

Solution: 2n+1=2×2n2^{n+1} = 2 \times 2^n  which is divisible by 22.

15. Find the total number of even numbers between 11 and 200200.
Solution:
Even numbers between 11 and 200200 form an arithmetic sequence:

2,4,6,,200.2, 4, 6, \dots, 200.

The nn-th term of an arithmetic sequence is given by:

an=a+(n1)d.a_n = a + (n-1)d.Here, a=2a = 2, d=2d = 2, and an=200a_n = 200, Solve for nn:

200=2+(n1)×2200=2nn=100.200 = 2 + (n-1) \times 2 \quad \Rightarrow \quad 200 = 2n \quad \Rightarrow \quad n = 100.Answer: There are 100100 even numbers between 11 and 200200.

16. Prove that the product of two consecutive even numbers is always divisible by 88.
Solution:
Let the two consecutive even numbers be n=2kn = 2k and n+2=2k+2n+2 = 2k+2.
The product is:

n×(n+2)=2k×(2k+2)=4k(k+1).n \times (n+2) = 2k \times (2k+2) = 4k(k+1).

  • One of kk or k+1k+1 is always even, making 4k(k+1)4k(k+1) divisible by 8.

Answer: The product is always divisible by 8.

 

17. Find the sum of all even numbers between and .
Solution:
Even numbers between 1 and 100100 form an arithmetic sequence:

2,4,6,,100.2, 4, 6, \dots, 100.

Number of terms (nn):

100=2+(n1)×2n=50.100 = 2 + (n-1) \times 2 \quad \Rightarrow \quad n = 50.Sum of an arithmetic sequence:

Sn=n2×(a+l).S_n = \frac{n}{2} \times (a + l).Here, n=50n = 50, a=2a = 2, l = 100:

Sn=502×(2+100)=25×102=2550.S_n = \frac{50}{2} \times (2 + 100) = 25 \times 102 = 2550.

Answer: The sum is 25502550.

 

18. Can the sum of 77 odd numbers be even?
Solution:
The sum of odd numbers follows this rule:

  • Odd + Odd = Even
  • Adding another odd number to an even sum makes it odd.

Thus, the sum of 77 odd numbers is always odd.

 

19. If 𝑥 is an odd number,  prove that x21x^2 – 1 is always divisible by 88.
Solution:
Let x=2k+1x = 2k+1 (general form of an odd number).

x21=(2k+1)21=4k2+4k+11=4k(k+1).x^2 – 1 = (2k+1)^2 – 1 = 4k^2 + 4k + 1 – 1 = 4k(k+1).

  • k(k+1)k(k+1) is always even (product of two consecutive integers).
  • Therefore, 4k(k+1)4k(k+1) is divisible by 8.

Answer: x21x^2 – 1 is always divisible by 88.

 

20. Find all even numbers divisible by both 33 and 44 between 11 and 100100.
Solution:
An even number divisible by 33 and 44 must also be divisible by their LCM.

LCM of 3 and 4=12.\text{LCM of } 3 \text{ and } 4 = 12.

Even numbers divisible by 1212:

12,24,36,48,60,72,84,96.12, 24, 36, 48, 60, 72, 84, 96.

Count of numbers: 88.

Answer: The numbers are 12,24,36,48,60,72,84,9612, 24, 36, 48, 60, 72, 84, 96

 

More Practice Questions

 

1. What is the sum of all odd numbers between 11 and 9999?

2. If xx is an even number, prove that x2+3xx^2 + 3x is always even.

3. How many odd numbers between 11 and 10001000 are divisible by 55?

4. Prove that the difference between the squares of two consecutive odd numbers is always divisible by 88.

5. If nn is odd, prove that n3nn^3 – n is divisible by 88.

6. Find the sum of all even numbers between 11 and 200200 that are divisible by 55.

7. Find the smallest even number greater than 100100 that is divisible by 77.

8. If xx is odd,  x21x^2 – 1 is divisible by 44 or not ?

9. Determine count of all even numbers between 11 and 500500 that are divisible by both 66 and 88.

10.  Product of three consecutive odd numbers is odd or even ?

11. How many odd numbers between 11 and 300300 are divisible by 99?

12. If xx is an even number and yy is an odd number,  x2y2x^2 – y^2 is always even or odd ?

13. Find the sum of all odd numbers between 200200 and 400400.

14. How many even numbers between 11 and 10001000 are divisible by both 44 and 55?

15.  The sum of any nn consecutive even numbers is divisible by n or not ?.

16. How many odd numbers between 11 and 500500 are divisible by both 33 and 77?

17. Find the smallest odd number greater than 10001000 that is divisible by 1111.

18.  The product of any three consecutive even numbers is always divisible by 4848 ?

19. If nn is an odd number, prove that n3+nn^3 + n is always divisible by 44.

20. Find all even numbers between 11 and 200200 that are divisible by 33 but not by 99.